A man walks at 6km/h and runs at 8km/h. He covers 6km in 50min partly by running and partly by walking. 1 . For how long did he walk? 2. What distance did he cover walking?
Answers
Answer:
When he walks,
Speed = 6 km/h
Distance = x km ( suppose)
Thus, the time taken by him in walking = \frac{x}{6}
6
x
hours,
( Because, time = distance/speed )
Now, when he runs,
Speed = 8 km/h
Distance = (6-x) km, ( Because, he covers 6 km partly by walking and partly by running )
Thus, the time taken by him in walking = \frac{(6-x)}{8}
8
(6−x)
hours,
Since, According to the question,
The total time taken by him in both walking and running = 50 minutes
⇒ \frac{x}{6}+\frac{6-x}{8}=\frac{50}{60}
6
x
+
8
6−x
=
60
50
⇒ \frac{4x+18-3x}{24}=\frac{5}{6}
24
4x+18−3x
=
6
5
⇒ \frac{x+18}{24}=\frac{5}{6}
24
x+18
=
6
5
⇒ 6x+108=120\implies 6x=12 \implies x =26x+108=120⟹6x=12⟹x=2
Thus, The distance he covers in walking = 2 km,
And, the distance he covers in running = 6 - 2 = 4 km.
I hope it helps you alot.
