Math, asked by adi9650788801, 2 months ago

A man walks at 6km/h and runs at 8km/h. He covers 6km in 50min partly by walking.​

Answers

Answered by nikunjc971
0

Answer:

Thus, The distance he covers in walking = 2 km, And, the distance he covers in running = 6 - 2 = 4 km

Step-by-step explanation:

viWalking speed = 6km/hr or

60min

6km

Running speed = 8 km/hr or

60min

8km

Total distance to cover ⇒6km

Total Time taken = 50 min

Let the distance covered while waking = (x)km

running = (6-8)

∴ according to ques :-

6/60

x

+

8/60

6−x

=50

⇒60×

2

1

[

3

x

+

4

6−x

]=50

12

4x+18−3x

=

3

5

1(x−18)=5×4

x=20−18⇒2,

x=2

6−x=4

∴ Now,

(ii) Distance covered while walking ⇒2km

(i) He walked for (

6/60

x

)min⇒(

6

2

×60)

3

60

⇒20min

Answered by sohalsukhdeep23
0

Answer:

I hope it helps you.

Mark me brainliest.

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