Question

A man walks at a speed of 1m/s and covers a certain distance in some time. But if he walks at a speed of 3m/s, he covers an additional distance of 15m in the same time.What is the distance he actually covered? ​

Answer 1

Solution:-

★ Case 1 :

Here , given.

• Speed = 1 m/s
• let us assume it as S1
• Let distance travelled be d1
• Let us assume distance travelled be t

Speed = Distance/Time

S1 = d1/t1 = d1/t

1 = d1/t

t = d1 .…… 1

★ Case 2 :

Here , given.

• Speed = 3m/s let us assume it as S2
• Distance = 15m let us assume d2
• Since , here already given that the time of case 1 & 2 are equal . So , here also the time will be t

Speed = distance/time

S2 = d2/t3

3 = d1 + 15/t

t = d1 + 15/3 …… 2

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Now , finding the total distance

t = d1 = d1 + 15/3

→ 3d1 = d1 + 15

→ 3d1 - d1 = 15

→ 2d1 = 15

→ d1 = 15/2

→ d1 = 7.5 m

→ d2 = d1 + 15 = 7.5 + 15

→ d2 = 22.5

Total distance = d1 + d2

Total distance = 22.5 + 7.5

Total distance = 30 m

Hence , total distance = 30 m