Question

a man walks at a speed of 1m/s and covers a certain distance in some time. but, if he walks at a speed of 3m/s, he covers an additional distance of 15m in the same time. what is the distance he actually covered?

Answer 1

Answer:

Step-by-step explanation:

a man walks at a speed of 1m/s

covers a certain distance in some time.

Let the actual distance be x

if he walks at a speed of 3m/s

he covers an additional distance of 15m in the same time.

Let the additional distance be = x+15

1m/s     =    x km

3m/s    =    x+15 km

1m/s     =    x km

           x                                  (Cross multiplication)

3m/s    =    x+15 km

x+15 = 3x

Rearranging the terms we get

3x-x = 15

2x =15

x=15/2

x= 7.5 km

therefore if a man walks at a speed of 1m/s and covers a certain distance of 7.5 km

if he walks at a speed of 3m/s, he covers an additional distance of 15m=x+15 we already know the value of x now substitute in it we get =7.5+15 = 22.5km

 

therefore if a man walks at a speed of 1m/s and covers a certain distance of 7.5 km and  if he walks at a speed of 3m/s, he covers an distance of 22.5km