Question

A man walks at a speed of 6 km/hr for 1km and 8km/hr for next 1km. His average speed for the walk of 2km is n km/hr. Then n is​

Answer 1

v1=6km/hr

s1=1km

t1=1/6h

v2=8km/hr

s2=1km

t2=1/8h

Average speed(n)=Total distance/total time

n= (1+1)/(1/6+1/8)

n= 2/(7/24)

n=(2×24)/7

n=48/7

n=6.85km/h