Question

A man walks at the speed of 7 km/hr and runs at the speed of 56 km/hr. How much time will the man require to cover the distance of 28 km, if he covers half (first = 14 km) his journey walking and half of his journey running?

Answer 1

$\underline{\bold{Given}}$

A man's walking speed = 7km / h.

A man's running speed = 56km / h.

$\underline{\bold{To\:Find}}$

Time required to cover the distance of 28km.

$\bold{We\:Know\:That}$

$\boxed{\boxed{\bold{Time = \dfrac{Distance}{Speed}}}}$

$\bold{According\:To\:The\:Question}$

$\implies\bold{Time = \dfrac{Distance}{Speed} + \dfrac{Distance}{Speed}}$

$\implies\bold{Time = \dfrac{14km}{7km/hr} + \dfrac{14km}{56km/hr}}$

$\implies\bold{Time = \dfrac{9}{4} = 2.25}$

$\implies\bold{2\:hours\:25\:minutes}$

The time taken by a man to cover the distance of 28km is 2 hours 25 minutes.