Question

A man walks for 1 minute with a speed of 1 m/s and he runs for the next minute with a speed of 3 m/s along a straight track .t he total distance covered is

Answer 1

Given,
Time1=1 min=60 sec
Speed1= 1m/s

Time2= 1min=60sec
Speed2=3m/s

For first distance,
distance=speed×time
distance=1×60
distance=60m=60/1000km=3/50 km

For second distance,
distance=speed × time
distance=3×60
distance=180m=180/1000 km=9/50km

Total distance,
first dis.+second dis.
3/50+9/50
0.24km

Means we can say that total distance is 240 m