A man walks for 1 minute with speed of 1 ms-1 and then runs for next minute with speed of 3ms-1 along a straight track .the average speed of man is
Answers
The first minute
Speed = 1 m / s
This means that he covers 1 m in 1 s.
In 1 minute there are 60 s .
So the man covers 60 m in 60 s.
Distance is 60 m ..................................(1)
The next minute
The speed is 3 m/s
This means that he covers 3 m in 1 s
In 1 minute there are 60 s
So the man covers 3*60 m
==> 180 m ..............................(2)
Total distance
Total distance [ by adding (1) and (2) ]
==> 180 m + 60 m
==> 240 m
Speed = distance / time
time is 2 minutes = 2*60 s = 120 s
Speed = 240 m / 120 s
==> 2 m / s
The average speed is 2 m / s.
Hope it helps you
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Answer:
2m/s
Explanation:
Total distance covered by the man
1ms for 1 minute = 1 x 60 = 60m
3ms for 1 minute = 3 x 60 = 180m
Total distance = 60 + 180
= 240m
Total time = 2 minute
= 120 s
average speed = distance/ time
240/120
= 2 ms
Hence, 2ms is the average speed.