a man walks for x hours at a speed of (x+1)km/h and cycles for (x-1) hours at a speed of (2x+5) km/h. If the total distanced travelled is 90 km. find x
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Total distance covered walking = x^2 + x) km
Total distance covered cycling = (2x^2 + 3x -5) km
A/q,
x^2 + x + 2x^2 + 3x - 5 = 90
Total distance covered cycling = (2x^2 + 3x -5) km
A/q,
x^2 + x + 2x^2 + 3x - 5 = 90
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