a man walks from his home to town 6km away at 4km per hour and return again to his home at 12km per hour using a Tonga what is the man's average speed for the double journey
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Answer:
Given,
distance d =6 km
s1 =4km/h
s2 = 12km/h
t1 = 6/4
=> 1.5s
t2=6/12
=0.5s
Average speed =6×2/1.5+0.5
=> 12/2
=> 6km/ h
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@GauravSaxena01
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