Math, asked by Harihara, 1 month ago

A man walks from his house at an average speed of 5 km per hour and reaches his office 6 minutes late. If he walks at an average speed of 6 km/h he reaches 2 minutes early. The distance of the office from his house is​

Answers

Answered by stebinbenny8136
1

Answer:

in between 5.5Km and 5.8 km

Step-by-step explanation:

if he walks in a speed of average 5km/h he needs 6 minutes more to reach his office that is in 66 minutes he will reach his office. 5km/h can be converted into 83.33m/m. in 1 minute if he walks 83 meter he will reach his office in 66 minutes then 66*83.33=5,499.78 that is 5.5km

if he walks in a speed of average 6km/h he will reach his office in 58 minutes. that is in 1 minute he walks 100 meters, then in 58 minutes he walks 5,800 meters that is 5.8km

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