Question

A man walks from point a and b in 2 hours and from B to C in 1 hour. A)What will his average speed and velocity be at point B?
(B).what will his average speed and average velocity be at point C?​

Answer 1

Explanation:

Average speed =

totaltime

totaldistance

Time taken to go to the market =

speed

distance

=

5

2.5

hour=

2

1

hours=30 minutes

Time taken to return back =

speed

distance

=

7.5

2.5

hour=1/3hours=20 minutes

Distance travelled in 10 minutes while returning back=

60

10

×7.5=1.25km ( Speed is constant at 7.5 km/hr )

Hence Distance traveled in 40 minutes(30 mins towards the market and 10 mins towards home) =2.5+1.25=3.75km

So average speed in 0 to 40 minutes =

60

40

hr

3.75km

=

8

45

km/hr