Question

A man walks from point A to B through semicircular track ACB as shown in figure. What is his distance and displacement? Radius of Semi Circular track ACB OB = OA = r (a) Distance = 2πr, displacement = 2πr (b) Distance = πr, displacement = 2πr (c) Distance = 2πr, displacement = 2r (d) Distance = πr, displacement = 2r

Answer 1

Answer:

D

Explanation:

Hope it will HELP YOU..

Answer 2

Answer:

Option d is correct.

Distance =  πr

Displacement = 2r

Explanation:

In the figure, Semi circular track ABC is drawn.

When a man walks from point A to point B through the semi-circular track. His displacement is equal to the minimum distance between the initial point and final point which is equal to the diameter of the circular track.

Given: The radius of the circular track is =  r

So, diameter of the circular track  = 2xr = 2r

Therefore, displacement = 2r

Distance covered by man is equal to the circumference of the semi-circular track = $\frac{2 \pi r}{2}$ = πr.

So, option d is correct.

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