A man walks from point A to B through semicircular track ACB as shown in figure. What is his distance and displacement? Given: Radius of Semi circular track ACB is OB=OA= r *
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Answered by
5
Answer:
The distance covered by the person = πr ( as perimeter of a circle is 2πr, hence the perimeter of the semicircle is πr )
the displacement (shortest distance )covered = diameter of the semicircle .
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Answered by
5
Answer:
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DISTANCE = 3.14r
DISPLACEMENT = 2r
Explanation:
as OB = OA = r
DISTANCE by FOLLOWING ACB MEANS ARC = π r (half of circle)
= 3.14r (approx.)
AND AS WE KNOW DISPLACEMENT IS SHORTEST POSSIBLE PATH :
⇒ along the diameter = 2r
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