A man walks on a straight road from his home
to a market 2.5 km away with a speed of
5 km/h. Finding the market closed, he instantly
turns and walk back home with a speed of
7.5 km/h. The average speed of the man over
the interval of time 0 to 40 minutes is
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Answer:
total distance between home and market=2.5 km
time taken by man to go market from home= 2.5/5=30 min
time taken to return from market to home= 2.5/7.5=20 minutes
total time taken for the whole journey =30+20=50 min
distance covered in next 10 minutes= 7.5×10/60=1.25 km
total distance covered=2.5+1.25=3.75 km
now, average speed= 3.75÷40/60 = 5.62 km/hr
Explanation:
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