Question

A man walks on a straight road from his home to a market 2.5 km away
with a speed of 5 km/h. Finding the market closed, he instantly turns
and walks back home with a speed of 7.5 km/h. What is the (a) magnitude
of average velocity and (b) average speed of the man over the time interval
O to 50 min.
1) O, 4 kmph
2)0,6 kmph
3) 0,8 kmph
4) 0,12 kmph



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Answer 1

Answer:

opt 2

Explanation:

velocity=displacement/time

displacement=0 hence velocity=0

speed=total distance/total time

v=(5)/5/6

 =6 kmph

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