Question

a man walks on a straight road from his home to a market 3 km waay with a speed of 6km/h finding the market closed he instantly turns and walk back with a speed of 9km/h what us tge magnitude of average velocity

Answer 1

first find the time taken for initial journey as 3/6=1/2hours and then for final 3/9=1/3 now avgVelocity is equal to total displacement / time interval so displacement is 3 so ansmer will be 3.6km/hr