A man walks on a straight road from his home to a post office letter box, 1 km away with a speed of 1 m/s. Dropping a letter immediately turns and runs back home with a speed of 2 m/s. What is the magnitude of average velocity and the average speed for the whole path.
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1
Answer:
Sorry...but I think u can get the answer from teachers ...rather than we students ...but I think this question is in H.C Verma
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Answer:
let , time be t
In 1st case,
distance, s = 1km=1000m
speed , v is 1 m/s
time, t (a)= 1000 sec
In 2nd case.
distance , s= 1000m
speed=2m/s
time, t(b) =1000/2=500sec
total distance is 2000 m
total time is 1500 sec
total displacement is 0m
so, average speed is total distance/total time=4/3 m/s
average velocity is displacement /time=0
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