Question

a man walks on a straight road from his home to market 2.5 km away with a speed of 5 kilometre per hour finding the market closed hi instantly turns and walk back home with a speed of 7.5 km per hour the average speed of a man over the interval of time zero to 40 minutes is equal to ​

Answer 1

here is your answer mate...

Speed of the man = 7.5 km/h

Distance travelled in first 30 min = 2.5 km

Distance travelled by the man (from market to home) in the next 10 min

= 7.5 × 10/60 = 1.25 km

Net displacement = 2.5 – 1.25 = 1.25 km

Total distance travelled = 2.5 + 1.25 = 3.75 km

Average velocity = Displacement / Time = 1.25 / (40/60) = 1.875 km/h

Average speed = Distance / Time = 3.75 / (40/60) = 5.625 km/h...

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