A man walks on a straight road from his home to market 3 km away with a speed of 6 km / h. The time taken by the man to go from his home to market equal
Answers
Answer:
Time taken by man ti go fro m his home to market,
t1=distancespeed=3km6km/h=12h=30min
Time taken by man to go from market to home,
t2=3km9km/h=13h=20min
Total time taken=t1+t2=12+13=−56h
=50min
(i) 0→30min
(a) Average velocity =displacementtime
=3.0km(1/2)h=6km/h
(b) Average speed =(path lenght)/(time) =(3.0 km )/((1//2) h)=6 km //h(ii)0 to 50 minTotalpath≤nthcoverad=3.0 +3.0=6.0 kmTotaldisplacement=(displacement 0 /(time)Totaldisplacement=zero
(a) Average velocity =displacrmrnttime
=0(5/6)h=0
(b) Average speed =→talpath≤n>htime
=6km(5/6)j=7.2km/h
(iii) 0→40min
Distance moved in 30min(omhome→market)=3.0km
Distance moved in 10min(ommarket→home)withspeed9 km //h=9xx (10)/(60) =1.5 km.So,displacement=3.0 -1.5 =1.5 kmTotalpath≤n>htravel≤d3.0+ 1.5=4.5 km(a)Avera≥velocity=(1.5km)/((400//60)h) =2.25 km //k(b)Avera≥speed=(4.5 km)/9(40.60)h) =6.75 km //h`
Explanation:
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- The time taken by the man to go from his home to market = 30 minutes
- A man walks on a straight road from his home to market 3 km away with a speed of 6 km/hour.
- The time taken by the man to go from his home to market = ?
- The time taken by the man to go from his home to market is 30 minutes.