A man walks on a straight straight road from his home to a market 2.5 kilometre away with a speed of 5 kilometre per hour finding the market closely he instantly turns and walk back home with a speed of 7.5 km per hour the speed of men over the interval of time 0 to 40 minutes is equals to what
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♧EXPLANATION♧
Speed of the man = 7.5 km/h
Distance travelled in first 30 min = 2.5 km
Distance travelled by the man (from market to home) in the next 10 min
= 7.5 × 10/60 = 1.25 km
Net displacement = 2.5 – 1.25 = 1.25 km
Total distance travelled = 2.5 + 1.25 = 3.75 km
Average velocity = Displacement / Time = 1.25 / (40/60) = 1.875 km/h
Average speed = Distance / Time = 3.75 / (40/60)
= 5.625 km/h
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