a man walks on straight road from his home to market 2.5 km away with the speed of 5 km/h. finding the market closed, he instantly turn and walks home with speed of 7.5km/h.
what is the magnitude of average velocity and average speed of man over the interval of time (a) 0 to 30 min (b) 0 to 50 min.
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Answer:
Explanation:
Distance = 2500 m
Speed v 1 = 5 km/h = 25/18 m/s
v=s/t = 25/18 = 2500/t = 18/25 = t/2500 = 18*2500/25 = t
t 1 = 1800 s (30 minutes)
Speed v 2 = 37.5/18 = 375/80 m/s
180/375 = t/2500 = t = 1200 s (20 minutes)
Now, average speed = total distance / total time
5000/3000 = 1.67 m/s
average velocity = 0 m/s
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