Question

A man walks ona straight road from his home to a market 2.5 km away with a speed of Skmh Finding the market closedm he in stantly turns and walks back home with a speed of 7.5kmh? What is

the magnitude of average velocity and average speed of the man

over the time interval O to 50 min ?​

Answer 1

Answer:

Average velocity = Total Displacement/ Total Time =0m/s^2

Because, at the end displacement = 0 m.

Answer 2

Answer:

Answer

Average velocity = Total Displacement/ Total Time =0m/s

2

Because, at the end displacement = 0 m.

please mark me the brainliest thank you !!