Question

a man Walks up a stationary escalator in 90 seconds when this man stands on a moving escalator he goes up in 60 Seconds the time taken by the man to walk out the moving escalator is

Answer 1

Take distance as 'd'

Speed while walking up a stationary escalator- d/90


Speed while standing on a moving escalator- d/60

Total speed =d/60+d/90= 3d/180 + 2d/180= 5d/180 = d/36

So, speed = d/t = d/36

Ans. Required time is 36 seconds

Answer 2

Answer:

Time taken will be 36 sec.

Explanation:

Given that,

For stationary escalator

Time = 90 sec

For moving escalator

Time = 60 sec

Let the distance be x.

We know that,

The speed is equal to the distance divided by the time.

In mathematical terms,

$v=\dfrac{d}{t}$

Where, v = speed

d = distance

t = time

Now put the value into the formula

For stationary escalator,

$v' =\dfrac{x}{90}$

For moving escalator ,

$v'' =\dfrac{x}{60}$

Relative velocity is

$v=v'+v''$

$v=\dfrac{x}{90}+\dfrac{x}{60}$

$v=\dfrac{5x}{180}$

$v=\dfrac{x}{36}$

Hence, Time taken will be 36 sec.