A man walks up a stationary escalator in 90sec. When this man stands on a moving escalator he goes up in 60 sec. The time taken by the man to walk up the moving escalator is
Answers
1)Let
v = walking speed of person
u= escalator speed
Let the length of escalator be 'L'.
The person walks up the stationary escalator in 90s.
L = 90 v => v = L / 90.
2)The escalator moves a distance L in 60s.
L = 60u
=> u = L / 60.
3)When walking up the moving escalator , the net speed = v + u
Time taken = L / ( v + u ) = L / ( L /90+ L / 60 )
= 36s.
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Answer:-
Final Answer :36s
1)Let
v = walking speed of person
u= escalator speed
Let the length of escalator be 'L'.
The person walks up the stationary escalator in 90s.
L = 90 v => v = L/90
2)The escalator moves a distance L in 60s.
L = 60u
=> u = L/60.
3)When walking up the moving escalator , the net speed = v + u
Time taken = L / (v + u) = L/ (L/90+ L/60)
= 36s.