Question

A man walks with a speed of 5 ms-1 northwards and then turn to his right to move with the same speed. The change in velocity is: _                                                                           (1)

(a) 5 NE (b) 5 SE

(C) 5 SW (d) 25 SE

plzzz answer it's very urgent.....
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Answer 1

its C which is the correct option

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Answer 2

Answer:

The change in velocity is (b) 5√2 SE.

Step-by-step explanation:

It is given that the man is moving in the north direction with a speed of 5m/s.

Therefore, the speed of man moving towards north ($v_1$) = 5i

The man then turns right, i.e., east, and moves with the same speed.

Therefore, the speed of the man moving towards the east ($v_2$) = 5j

Change in velocity is given as

$v=v_2-v_1$

$v=5j-5i$

So, the magnitude of velocity is

$|v| = \sqrt{v_1^2+v_2^2}$

$|v|=\sqrt{5^2+5^2}$

$|v|=\sqrt{25+25}$

$|v|=\sqrt{50}$

|v| = 5√2 m/s

Direction of vector is given as

tan∅ = $\frac{5}{-5}$

tan∅ = -1

∅ = -45°

Therefore, it points out in the southeast direction.

Hence, the change in velocity is 5√2 m/s in the southeast direction.

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