A man walks with const speed 5km for 2hr. In a direction due E. then he walks 5 roit 3 km/h for 2hr in a direction due N and he runs for 10km in a direction 60 sec of west in next one hour . find Average velosity
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VRain,Person=VRain−VPerson=−12j^ (vertically down)
Thus, VRain−(5i^)=−12j^ or, VRain=5i^−12j^
Thus, direction is tan−1(125)=22o37′ east of vertical (+5,−12) means 4th quadrant, thus east of vertical.
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