A man wants to cut three pieces from a single piece of board of length 47m. The second piece is to be 3m longer than the shortest one and the third piece is to be twice as long as the shortest piece. What are the possible lengths of the shortest board if the third piece is to be at least 5m longer than the second?
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Answered by
3
Let the smallest piece be x.
therefore, second piece = x+3
third piece = 2x
If we add all the pieces , they must sum up to 47m
So, x + (x+3) + 2x = 47
or , 4x+3 = 47
or, 4x = 47-3
or, 4x = 44
or, x = 44/4
or, x = 11m
so, smallest piece x = 11m
second piece (x+3) = 11+3 = 14m
Third piece (2x) = 2×11 = 22m
Answer ) Smallest piece is 11m and the other pieces are 14m and 22m
therefore, second piece = x+3
third piece = 2x
If we add all the pieces , they must sum up to 47m
So, x + (x+3) + 2x = 47
or , 4x+3 = 47
or, 4x = 47-3
or, 4x = 44
or, x = 44/4
or, x = 11m
so, smallest piece x = 11m
second piece (x+3) = 11+3 = 14m
Third piece (2x) = 2×11 = 22m
Answer ) Smallest piece is 11m and the other pieces are 14m and 22m
Answered by
25
Smallest piece is 11m and the other two pieces are 14m and 22m.
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