Question

A man wants to make a temporary shelter for his car by making a ber-like structure with tarpaulin that covers all the four sides and the top of the car. If the height of the shelter is 2.5 m and its base dimensions are 4 m by 3 m, how much tarpaulin would be required? ​

Answer 1

$\:\:\:$

Area of tarpaulin required

= (area of four sides)+(area of the top)

= ${2(l+b)×h}+(I×b)$

=${2×(4+3)× 2.5)} m^2+(4×3) m^2$

=$(35+12) m^2$

=$47 m^2$