Question

A man was 24 years old when his son was born. If the present age of the man is five times the age of the son, find their respective present ages (A) 50 years; 10 years (B) 30 years, 6 years (C) 32 years, 8 years (D) 40 years, 16 years​

Answer 1

Answer:

Son's age= x years

Father's age= y

y = x+ 24

y= 5x

5x= x+24

4x= 24

x=6 years

Age of son is 6 years

Father is 30 years old

Step-by-step explanation:

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Answer 2

Answer:

(B) 30;6

Step-by-step explanation:

Lets name son's age as x

Man's age when son was born = 24

Present age of man = 5x

Son's age was 0 years at birth

Man's age is five times son's age

So, it is likely that it is (a) or (b)

So in the first option, son would be 10 years older, so man's age would have been 24+10 = 34, so it is not likely

In the second option, son is 6 years older, and man's age is 24+6 = 30

So the answer is (B) 30;6

Not necessary to mark me brainliest

This is just a more understandable explanation.