A man was 70 kg when he entered into an elevator.when the the elevator started he was 65 kg then he was 70 kg again.before stopping his weight was 73 kg..1.what was the elevators acceleration at the time the journey started and just before stopping.
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Answer:
-0.7 ms⁻² and 0.42ms⁻²
Explanation:
his mass m = 70/9.8 = 7.143
acceleration at start = 65/7.143 - 9.8 = -0.7
acceleration before stopping = 73/7.143 -9.8 = 0.42
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