Question

A man was engaged as typist for the month of February in 2009. He was paid ₹500 per day, but ₹100 per day were deducted for the days he remained absent. He received ₹9200 as salary for the month. For how many days did he work?
Please help me

Answer 1

Let :-

• Money paid for present days = P
• Money deducted for absent days = A

Given :-

• Money paid for present day = ₹ 500
• Money deducted for absent day = ₹ 100
• Monthly salary received by the man = ₹ 9200

Solution :-

• To calculate the no of days he work, at first we have to set up equation. Then calculate the value of P and A by solving equations.

Calculation begins :-

⇒ Present days + Absent days = Months of February

⇒ P + A = 28----------(i)

⇒ Money received for present days - Money deducted for absent days = Months of the salary of the man.

⇒ 500(P) - 100(A) = 9200

⇒ 500P - 100A = 9200-------(ii)

• Now multiplying by 500 in eq (I) then subtract :-]

⇒ 500P + 500A = 14000

⇒ 500P - 100A = 9200

• By solving we get here :-]

⇒ 600A = 4800 ⇒ 6A = 48 ⇒ A = 8

• Putting the value of A = 8 in eq (i) :-]

⇒ P + A = 28

⇒ P + 8 = 28

⇒ P = 28 - 8

⇒ P = 20

Hence,

• The man work in the month of February = 20 days

Answer 2

Answer:

$\huge \sf{\underbrace{\underline{Answer: -}}}$

Given :-

• A man was engaged as typist for a month of February in 2009.He was paid £500 per day.But £100 per day were deducted for the days he remains absent.

To prove :-

• For how many days did he work?

Answer :-

• In the month of February the man work in 20 days.

Solution :-

• Consider,

• Money paid for the given days be =x.
• Money which is deducted for absent days be=y.

Here,

• We should add both present and absent days first that is ;

• Month of February =Absent days+Present days.

x+y=28 (i ).

$\mathcal\purple{And ,}$

• According to the given question we should subtract
• The month salary of the man = Money which is taken for present days- Money which is deducted for absent days .

• 500 (x)-100 (y)=9200

• We can write it as,

• 500x-100y=9200.

• If we want to get answer we should multiply 500 in the given first equation and subtract it.

• This becomes,

• 500x+500y=14000
• 500x-100y =9200
• +600y=4800
• y=4800/600
• y=8.

$\mathcal\red{Now,}$

• Applying the value of y in eqn (i) we get that,

x+y=28(y=8)

• x+8=28
• x =28-8
• x =20.

Therefore ,

• In month of February the man work in 20 days.

Hope it helps u mate .

Thank you .