A man was engaged as typist for the month of February in 2009. He was paid ₹500 per day, but ₹100 per day were deducted for the days he remained absent. He received ₹9200 as salary for the month. For how many days did he work?
Answers
Answer:
Let the man worked as a typist for x days in the month of February 2009.
Then
absent in the month of February 2009 = (29-x) days
[we know that, maximum number of days in February is 29]
Total paid amount for working days
= Rs 500x
and
per day deduction when he remained absent = Rs 100
Total amount deducted for being absent
= Rs 100 × (29-x)
Given
salary received by man for thee month of February is Rs 9100
According to the question,
500x - 100×(29-x) = 9100
\implies⟹ 500x - 2900 + 100x = 9100
\implies⟹ 600x = 9100 + 2900
\implies⟹ 600x = 12000
\implies⟹ x = 12000 ÷ 600
\implies⟹ x = 20
\therefore∴ x = 20
Hence,
The man worked for 20 days
Answer:
Let :-
Money paid for present days = P
Money deducted for absent days = A
Given :-
Money paid for present day = ₹ 500
Money deducted for absent day = ₹ 100
Monthly salary received by the man = ₹ 9200
Solution :-
To calculate the no of days he work, at first we have to set up equation. Then calculate the value of P and A by solving equations.
Calculation begins :-
⇒ Present days + Absent days = Months of February
⇒ P + A = 28----------(i)
⇒ Money received for present days - Money deducted for absent days = Months of the salary of the man.
⇒ 500(P) - 100(A) = 9200
⇒ 500P - 100A = 9200-------(ii)
Now multiplying by 500 in eq (I) then subtract :-]
⇒ 500P + 500A = 14000
⇒ 500P - 100A = 9200
By solving we get here :-]
⇒ 600A = 4800 ⇒ 6A = 48 ⇒ A = 8
Putting the value of A = 8 in eq (i) :-]
⇒ P + A = 28
⇒ P + 8 = 28
⇒ P = 28 - 8
⇒ P = 20
Hence,
The man work in the month of February = 20 days