Math, asked by chetnavij9105, 1 year ago

A man was n years old in the year n^2. How old was he in 1960?

Answers

Answered by Utkarsheenikairvi
2

Let's find the two square years that 1960 is between.

√1960 = 44.27188724, which is between 44 and 45.

Therefore 1960 is between the two square years 44� = 1936 and 45� = 2025.

So he was either born in the year 1936-44 = 1892 or the year 2025-45 = 1980.

He couldn't have been born in 1980 since 1960 was 20 years before he was born!

So he was born in 1892 (and is now dead or else 122 years old).

Since 1960 was 1960-1892=68 years after 1892, he was 68 in 1960.

[ Incidentally what you can learn from this problem is that if you know

somebody who was born in 1980, you can tell them that they will be n in the

year n�. Such a person would now be 2014-1980 = 34 years old. Do you know

anybody who is 34 now in 2014? If so, you can have fun telling them that. :) ]

Answered by brunoconti
1

Answer:

Step-by-step explanation:

the man was 44 years old in 1936 = 44^2.

in 1960 he became 44 + 24 = 68 years old.

if the man is 45 years old in 2025 = 45^2, then he would not have be en born in 1960.

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