Physics, asked by aryan1078raj, 10 months ago

A man was sitting 2 m east of Shyam, went 2^½+ m north-east and then 3 m north to meet Ram. Find thedistance travelled by man and displacement in this process.​

Answers

Answered by bestwriters
0

The distance traveled by man and displacement in this process are 4.41 meter and √(19) meter.

Explanation:

The position is drawn in the image below.

SX = √((SM)² + (MX)²)

SX = √((2)² + (1.41)²)

SX = √(4 + 6)

∴ SX = √(10) m

Now, the displacement is given as:

SR = √((SX)² + (XR)²)

SR = √(10 + 9)

∴ SR = √(19) m

The distance traveled is given as:

MR = MX + XR

On substituting the values, we get,

MR = 1.41 + 3

∴ MR = 4.41 m

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Answered by ketanpatil2174
0

Explanation:

hope this helps you....

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