A man was sitting 2 m east of Shyam, went 2^½+ m north-east and then 3 m north to meet Ram. Find thedistance travelled by man and displacement in this process.
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The distance traveled by man and displacement in this process are 4.41 meter and √(19) meter.
Explanation:
The position is drawn in the image below.
SX = √((SM)² + (MX)²)
SX = √((2)² + (1.41)²)
SX = √(4 + 6)
∴ SX = √(10) m
Now, the displacement is given as:
SR = √((SX)² + (XR)²)
SR = √(10 + 9)
∴ SR = √(19) m
The distance traveled is given as:
MR = MX + XR
On substituting the values, we get,
MR = 1.41 + 3
∴ MR = 4.41 m
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