A man wearing a bullet proof vest stand still on roller skates.the total mass is 80 kg A bullet of mass 20 g is fired at 400m /s it is stopped by the vest and falls to the ground what is then the velocity of the man.
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Answer:
mass of man=80kg
velocity (u)of man=0m/s
mass of bullet=20g=0.02kg
velocity(u) of bullet=400m/s
velocity(v)of bullet=0m/s
To find final velocity of man
m1u1+m2u2=m1v1+m2v2
80×O+0.02×400=80v2+0.02×0
0+8=80v2+0
8=80v2
8/80=V2
1/10=v2
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