. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man? (a) 1 m/s (b) 0.1 m/s (c) 0.01 m/s (d) 0 m/s please write the explanation it is for a test
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Answer:
source:google
Explanation:
Explanation:
m
- mass of bullet
=
0.02 kg
M
- mass of man
=
80 kg
u
- initial velocity of bullet
=
400 m/s
U
- initial velocity of man
=
0 m/s
v
- final velocity of bullet
=
0 m/s
V
- final velocity of man
Using conservation of momentum,
initial momentum
=
final momentum
m
⋅
u
+
M
⋅
U
=
m
⋅
v
+
M
⋅
V
0.02
⋅
400
+
80
⋅
0
=
0.02
⋅
0
+
80
⋅
V
8
=
80
⋅
V
⇒
V
=
0.1 m/s
Therefore, the man moves with a velocity of
0.1 m/s
hope this helps
with love ,
pinkrosyqueen
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