A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man? *
Answers
Answered by
13
Answer:
0.1m/s
Explanation:
m - mass of bullet = 0.02 kg
M - mass of man = 80 kg
u - initial velocity of bullet = 400 m/s
U - initial velocity of man =0 m/s
v - final velocity of bullet = 0 m/s
V - final velocity of man
Using conservation of momentum,
initial momentum = final momentum
m⋅u+M⋅U=m⋅v+M⋅V
0.02⋅400+80⋅0=0.02⋅0+80⋅V
8=80⋅V⇒V=0.1 m/s
Therefore, the man moves with a velocity of 0.1 m/s
Answered by
1
Answer:
0.1m/s
Explanation:
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