a man wearing bullet proof jacket stands on a roller scate . total mass is 80 kg a bullet of mass 20 g fired at 400 m/s it is stopped by jacket and falls on ground what is then velocity of men
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Answered by
3
Answer:
p =MV
- p=0.02*400=8
Linear momentum is conserved
8=80*v
0.1 m/s is the answer
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Answered by
2
Answer: Here just apply law of conservation of momentum
let v be velocity of men
80*v=400*(20/1000)
80*v=8
v= 0.1 m/s
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