Question

A man weighing 16 pounds stand on the floor of an elevator. What force will be exerted on its floor when it (i)Descend with a uniform acceleration of 1 ft/sec2? (ii)Ascends with a uniform acceleration of 1 ft/sec2?​

Answer 1

Answer:

I) f=ma 16*1 =-16 2)16*1=+16

Answer 2

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\mathcal{\bf{{\underline{\underline{\huge\mathcal{...Answer...}}}}}}$

$\large\mathcal\red{solution}$

g=32.15ft/s²

1)

As the lift is descending with an acceleration 1ft/s²

So net gravitational acceleration acting on the body is =(32.15+1)ft/s²

=33.15ft/s²

Therefore...force exerted=(16×33.15)lb.ft/sec²=530.4

2)

As the lift is ascending with an acceleration 1ft/s²

So net gravitational acceleration acting on the body is =(32.15-1)ft/s²

=31.15ft/s²

Therefore...force exerted=(16×31.15)lb.ft/sec²=498.4

$\underline{\large\mathcal\red{hope\: this \: helps \:you......}}$