Question

A man weighing 50 kg supports a man of 20 kg on his hands. What is the work done by him when he is stationary​

Answer 1

Answer:

Here, m= 55+20= 75 kg

       s=  20 m.

(1) Work done on a horizontal road:-

     W= Fs cosθ= Fs cos900= 0    (as θ=900)

(2) Work done on an incline :-

     Given sinθ= [Equation]

W= Fs cosθ= (mgsinθ)s cos00

     = 75 x 10 x [Equation] x 20 x 1

W= 3000J