Question

A man weighing 50 kgf is standing on a wooden plank of 1m × 0.5m. What will be the pressure exerted by it on the ground?
1) 300 kgf/m2
2) 100 kgf/m2
3) 200 kgf/m2
4) 400 kgf/m2

Answer 1

Answer:

2) 100 kgf/m²

Explanation:

Given,

weight of the man = 50 kgf

area of the plank = 1m × 0.5m

We know that,

Pressure = Force/unit area

therefore,

pressure exerted by the man on the ground

$= \frac{50 \: kgf}{1 \: m \times 0.5 \: m} \\ = \frac{50 \: kgf}{0.5 \: {m}^{2} } \\ = \frac{500 \: kgf}{5 \: {m}^{2} } \\ = 100 \: kgf/ {m}^{2}$