Question

A man weighing 60 kg is in a lift moving down with an acceleration of 1.8 ms-2. The force exerted by the floor on him is

Answer 1

we know that Force will be always equal to Normal

so, F=ma

F=60 *1.8 N

F=108 N

Therefore,The Force Exerted by the floor on the man Is 108 N

Answer 2

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