A man weighing 60 kg runs along the rail with a velocity of 18 km/hr and jumps into a car of mass 1 quintal standing on the rail . calculate the velocity with which car will start travelling along the rail
shyamsashvat:
answer is 3m\s not 1.87
Answers
Answered by
27
mass of man(m1) = 60 kg
initial velocity of man(u1) = 18km/h or 5m/s
mass of car(m2) = 1 quintal or 100kg
initial velocity of car(u2) = 0m/s
according to law of conservation of momentum Momentum before collision(P1)= momentum after collisiion(P2)
m1u1 + m2u2 = m1v1+ m2v2 or m1+m2(v)
60kg x 5m/s +100kg x 0m/s= 100kg +60kg (v)
300kgm/s+0kgm/s=160v
v= 300/160kgm/s = 1.25m/s
initial velocity of man(u1) = 18km/h or 5m/s
mass of car(m2) = 1 quintal or 100kg
initial velocity of car(u2) = 0m/s
according to law of conservation of momentum Momentum before collision(P1)= momentum after collisiion(P2)
m1u1 + m2u2 = m1v1+ m2v2 or m1+m2(v)
60kg x 5m/s +100kg x 0m/s= 100kg +60kg (v)
300kgm/s+0kgm/s=160v
v= 300/160kgm/s = 1.25m/s
Answered by
6
Answer:
Hope you have received your answer...
Attachments:
Similar questions