Question

A man weighing 60 kg runs along the rails with a velocity of 18 km/h and jumps into the car of mass 1 quintal (100kg) standing on the rails. Calculate the velocity with which car will start travelling along the rails.​

Answer 1

Answer:

Heya mate⭐

______________

Mass of man (m1)=>60kg

Mass of car (m2)=>100kg

initial velocity of man(u1) =>18km/h =>5m/s

Initial velocity of car (u2)=>0km/h =>0m/s

Final velocity of man(v1)=>v

Final velocity of car (v2)=>v

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According to law of conservation of momentum

m1u1+m2u2=>m1v1 + m2v2

=>300+0 =>60v +100v

=>v =>300/160

=>1.875m/s

hope helps⭐

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\pink{Answer:-}$

⏩ **Mass of the man (m1) = 60 kg

*Initial velocity of the man (u1)= 18 km/h = 5 m/s

** Mass of the car (m2) = 100 kg

*Initial velocity of the car (u2)= 0

→After the man jumps into the car, let their common velocity be v.

Applying the law of conservation of momentum,

Total momentum after jump= Total momentum before jump.

(m1 + m2) v= m1u1 + m2u2

= (60 + 100) v= 60 × 5 + 100 × 0

=>160v= 300

=>v= 300/160

=> v= 1.875 m/s [The required solution..]

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Hope it helps..:-)

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