Question

a man weighing 70 kg carries a weight of 10kg on the top of a tower hundred metre height calculate the work done by the man if the value of g is 10 metre per second square ​

Answer 1

8 × 10⁴ J

Given:

Total Mass (m) = 70 + 10 = 80 kg

Total distance (s) = 100 m

g = 10 m/s²

Solution:

As We know,

W = F×s

= mg × s

Substituting the value I get,

= 80 × 10 × 100

= 8 × 10⁴ J

Therefore the required work done is 8 × 10⁴ J

Answer 2

Answer:

Given :-

• A man weighing 70 kg carries a weight of 10 kg on the top of a tower 100 m height.
• The value of g or acceleration due to gravity is 10 m/s².

To Find :-

• What is the work done by the man.

Formula Used :-

$\clubsuit$ Work Done Formula :

$\bigstar \: \: \sf\boxed{\bold{Work\: Done =\: mgh}}\: \: \: \bigstar$

where,

• m = Mass
• g = Acceleration due to gravity
• h = Height

Solution :-

First, we have to find the total mass carried :

Given :

• Mass of Man = 70 kg
• Mass of carried things = 10 kg

So, the total weight carried :

$\mapsto \sf Total\: Mass\: Carried =\: 70\: kg + 10\: kg$

$\mapsto \sf\bold{Total\: Mass\: Carried =\: 80\: kg}$

Hence, the total mass carried is 80 kg .

Now, we have to find the work done by the man :

Given :

• Mass = 80 kg
• Acceleration due to gravity = 10 m/s²
• Height = 100 m

According to the question by using the formula we get,

$\implies \sf\bold{\underline{Work\: Done_{(Man)} =\: mgh}}$

$\implies \sf Work\: Done_{(Man)} =\: 80 \times 10 \times 100$

$\implies \sf Work\: Done_{(Man)} =\: 800 \times 100$

$\implies \sf\bold{Work\: Done_{(Man)} =\: 80000\: J}$

$\therefore$ The work done by the man is 80000 Joules .