Physics, asked by urvi7760, 9 months ago

A man weighing 70kg carries a weight of 10kg on the top of a tower 100m high. Calculate the work done by the man.


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Answers

Answered by Anonymous
4

 \large \bold{ \underline{ \underline{ \: Answer : \:  \:  \: }}}

 \to Work done = 80000 Joule

 \large \bold{ \underline{ \underline{  \: Explanation  : \:  \:  \: }}}

 \to Mass ( m ) = 70 + 10 = 80 kg

 \to Height ( h ) = 100 m

 \large \fbox{ \bold{ \fbox{ \:  \: Work  \: done = mgh  \:  \: }}}

 \to Work done = 80 × 10 × 100

{ Since , g = 10 m/s² }

 \to Work done = 80000 Joule

Answered by agastyaaman
2

Answer:

80000 Joules will b the answer

Explanation:

Total mass = 70kg + 10kg

                  = 80 kg

Now , we know that :-

Work done = mgh

                   = 80kg * 10 m/s^2 * 100m (g = 10m/s^2)

                   = 80000 Joules

Hope u all understood the answer , THANK U !

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