Question

a man weighing 70kg carries a weight of 10kg to top of tower 100m high. calculate work done.

Answer 1

given :
weight of the man = 70kg
weight of the thing carried = 10kg
height of the tower = 100m

need to find out :
the work done

solution :
total weight = 70+10 = 80kg
work done = mgh
                 = 80 * 10 * 100 
                 = 80,000 J
therefore the work done = 80,000 J

Answer 2

Given,

Weight of a man = 70 Kg

The man carries a weight of = 10 Kg

Height of a tower = 100 meters

To find,

The total work done.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Weight of an object (W)

Weight of an object (W)= Mass of the object (m) x gravitational acceleration (a) (Equation 1)

Also,

Work done (W)

= Mass of the object sound the work (m) x gravitational acceleration (a) x height (h)

From equation 1, we get;

= Weight of an object (W) x height (h) {Equation 2}

Now, by using equation 2, we get;

Work done by the man, carrying the additional weight, in reaching the top of the tower

= {Total weight carried} x height (h)

= { 70 + 10 } x 100 meters

= 80 Kg m/s x 100 meters

= 8000 joules = 8 kilojoules = 8 KJ

Hence, the total work done by the man, carrying the additional weight, in reaching the top of the tower is equal to 8000 Joules.