A man weighs 60 N on the surface of the earth. What is his weight at a depth D= R/4
in side the
earth
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Answered by
3
Explanation:
W=m×g
g=GM/R^2=9.8 m/s^2
Here R=R/4 (its in depth)
g=GM/(R/4)^2
=GM/R^2/16
=GM/(R^2×16)
But, value of GM/R^2 is 9.8
W=mg/16
Thus the weight will be 16 times less than the weight on the surface of earth.
Weight at depth=60/16
=3.75 N
The weight at a depth will be 3.75 N.
Answered by
6
here is ur answer mate in this attachment.
45 N. ....... ...
..
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