Physics, asked by Ramaraju143, 11 months ago

A man weighs 60 N on the surface of the earth. What is his weight at a depth D= R/4
in side the
earth​

Answers

Answered by Anonymous
3

Explanation:

W=m×g

g=GM/R^2=9.8 m/s^2

Here R=R/4 (its in depth)

g=GM/(R/4)^2

=GM/R^2/16

=GM/(R^2×16)

But, value of GM/R^2 is 9.8

W=mg/16

Thus the weight will be 16 times less than the weight on the surface of earth.

Weight at depth=60/16

=3.75 N

The weight at a depth will be 3.75 N.

Answered by yuvraj309644
6

here is ur answer mate in this attachment.

45 N. ....... ...

..

Attachments:
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