Question

A man weighs 80 kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2 What would be the reading on the scale (g 10 m/s?

Answer 1

apparent weight = true weight + loss of weight due to upward uniform acc.
let apparent weight be x
x=80+40
x=120kg =reading of weight on scale